753x^2+199=242

Solution for 753x^2+199=242 equation:

753x^2+199=242

We move all terms to the left:

753x^2+199-(242)=0

We add all the numbers together, and all the variables

753x^2-43=0

a = 753; b = 0; c = -43;
Δ = b2-4ac
Δ = 02-4·753·(-43)
Δ = 129516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{129516}=\sqrt{4*32379}=\sqrt{4}*\sqrt{32379}=2\sqrt{32379}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{32379}}{2*753}=\frac{0-2\sqrt{32379}}{1506}
=-\frac{2\sqrt{32379}}{1506}
=-\frac{\sqrt{32379}}{753}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{32379}}{2*753}=\frac{0+2\sqrt{32379}}{1506}
=\frac{2\sqrt{32379}}{1506}
=\frac{\sqrt{32379}}{753}
$